Rich,

Anything coming from a user should be escaped. I'd rather not run the risk
of having control characters or other similar SQL injection tricks.

Either way - it's good to think ahead just in case anything you put into
the database (i.e. strings with ' or " or other characters) won't show up
with the extra slash there.

-Dash

You worry too much about your job.  Stop it.  You're not paid enough to
worry.

On Sat, 9 Nov 2002, Rich Gray wrote:

> Erm.. isn't the addslashes() just needed to protect the SQL query?
>
> IMO the data in the db will not have any slashes embedded in normal
> circumstances, so there is no reason to stripslashes() any data coming from
> a database column...
>
> Rich
> -----Original Message-----
> From: Dash McElroy [mailto:dash.php@;westonefcu.org]
> Sent: 08 November 2002 16:53
> To: 'Zeus'; [EMAIL PROTECTED]
> Subject: RE: [PHP-WIN] mysql_fetch_array problem
>
>
> Zeus,
>
> 2 notes:
>
> 1. Data you insert into a database should be addslashes($varname) first (or
> another encoding) to protect against MySQL injection vulnerabilities. A nice
> stripslashes($varname) on the way out gets rid of the slashes. You could
> also use urlencode($varname) and urldecode($varname). Helpful for storing
> URL's.
>
> 2. mysql_fetch_array
> (http://www.php.net/manual/en/function.mysql-fetch-array.php) is nowhere to
> be found in your code. You're using mysql_fetch_field...
>
> Either way, this is what I do:
>
> $result = mysql_query("SELECT * FROM shoutbox BY ID desc LIMIT 5");
> $count = mysql_num_rows($result);
>
> if ($count > 0) {
>       for ($i=0;$i<$count;$i++) {
>               $row = mysql_fetch_array($result);
>               echo $row['time'] ."<br />".$row['name']."<br
> />".$row['message']."<br />\n";
>       }
> }
> elseif ($count == 0) {
>       echo "No results returned";
> }
> else {
>       echo "Invalid Query. MySQL error: ".mysql_error();
> }
>
> Please note - this code is off the top of my head, I have not actually tried
> it :)
>
> -Dash
>
> -----Original Message-----
> From: Zeus [mailto:zeus_dreamer@;myrealbox.com]
> Sent: Saturday, November 09, 2002 4:29 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-WIN] mysql_fetch_array problem
>
>
> I try to display mysql database using fetch_array but there seem to problem,
> i m new with PHP and mysql.
> I didn't quite sure, what's worng with my codes.i havent include the form
> yet.
>
> the error messages:
>  Warning: mysql_fetch_field(): supplied argument is not a valid MySQL result
> resource in c:\apache\htdocs\zeus\shoutbox.php on line 17
>
>
> code in shoutbox.php:
>
> <?PHP
>
> mysql_connect('localhost', 'zeus', 'pass') or die ("deadconnect");
> mysql_select_db('zeussama_db') or die ("no db");
>
> if($submit)
> {
>  $time=date("h:ia d/j/y");
>  $result=mysql_query("INSERT INTO shoutbox (id,name,message,time)","values
> ('NULL','$name','$message','$time')");
>  }
> ?>
>
>
> <?php
> $result = mysql_query("SELECT * FROM shoutbox BY ID desc LIMIT 5");
> while($r=mysql_fetch_field($result))
> {
>  $time=$r["time"];
>  $id=$r["id"];
>  $message=$r["message"];
>  $name=$r["name"];
>
>  echo "$time <br>";
>  echo "$name <br>";
>  echo "$message <br>";
> }
> ?>
>
> ================================
> :.zeus:.
> http://www.redrival.com/zeussama
>
>
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