Use eval ... although beware of the serious security implications.
> Hi.
> I'm changing my website to one based on My-SQL which will help with
> organization and searching etc. Hopefully, the code for all the pages
> will be stored in the database too.
> However, I cannot get PHP to parse / execute the code stored in the
> database. The script
>
> $query = mysql_query("SELECT * FROM pages", $link);
> $result = mysql_fetch_array($query);
> print $result['4'];
>
> gets the content of the page (column 4 of the database) but displays
>
> include("common/counter.php"); include("common/navbar.php");
>
> to the screen instead of opening and including these two files in the
> output.
>
> Is there something I need to do to the result to make it executable?
> Might I need a \n between the two lines of code?
>
> I'm using Win 98, Apache 1.3.19, PHP 4.2.0 and MySQL but I'm not sure
> which version! (fairly recent though)
>
>
>
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--
Dan Hardiker [[EMAIL PROTECTED]]
ADAM Software & Systems Engineer
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