try to echo $i in a separate file (lets say image.php) and in the main file do echo "<input type=image src=".image.php." border=0>";
-- Best regards, George Nicolae IT Manager ___________________ PaginiWeb.com - Professional Web Design www.PaginiWeb.com "Waldemar Brand Neto" <[EMAIL PROTECTED]> wrote in message 005f01c1edf9$7ca7dce0$[EMAIL PROTECTED]">news:005f01c1edf9$7ca7dce0$[EMAIL PROTECTED]... Thank you for the help. I put the header in the top ot the document and now it works. I need one more tip. The result is not the image itself, but the content of the Blob Field, how can I fix that? Thanks. Waldemar The source code: <?php header("Content-type: image/jpeg"); header("Content-Disposition: inline; filename=temp.jpg"); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <html> <head> <title>Teste.php</title> </head> <BODY BGCOLOR=#3366FF> <CENTER> <FORM> <h1> Kompatscher & Cia Ltda </h1> <hr> <?php $con = mysql_connect("**************************) or die ("Erro ao conectar!"); mysql_select_db("***********", $con) or die ("Erro ao selecionar a database!"); $comando="SELECT codigo,nome,material,temperatura,pressao,fluido,descricao,foto FROM cadgrupo WHERE codigo=010"; $res = mysql_query($comando,$con); $linha = mysql_fetch_array($res); echo "<TABLE ALIGN=CENTER>"; echo "<tr>"; echo "<td>"; echo "Foto"; echo "</td>"; echo "<td>"; $i= $linha['foto'] ; echo "<input type=image src=$i border=0>"; echo "</td>"; echo "</tr>"; echo "</TABLE>"; mysql_close($con); ?> </FORM> </CENTER> </BODY> </html> -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
