$query="select name,department,Leave_From,Leave_To,Leave_Total,Reason from
leaverequest where Staff_Number='$StaffNum'"
will work just fine.
(Enclose vars with single quotes)
----- Original Message -----
From: "Jack" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, September 03, 2001 10:35 AM
Subject: [PHP-WIN] Use the User Input Critia as part of Query! (Mysql)
> Dear all
> I had a form which ask user to input the Staff Number to be as part of the
> query, but when i execute it, it seems not working at all
>
> here is what i wrote in php
> The user input box is : $StaffNum
>
> $query="select name,department,Leave_From,Leave_To,Leave_Total,Reason from
> leaverequest where Staff_Number="<?print("$StaffNum");?>" and authorized
is
> null";
>
> But said there is error on this line, which is what i expected!!
>
> So could anyone pls tell me how i can get the varaible into part of the
> Query of Mysql?
>
> Thx
> jack
> [EMAIL PROTECTED]
>
>
>
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