I recently installed PHP on a Windows 2000 server and brought over a few
general PHP scripts (used on a Linux box), but have found a very
annoying difference that I am wondering if I can get rid of.
I us many checks in my programs with a simple !$var check -- which works
find in Linux, but I get a Warning message out of Windows whenever it
comes to this (but it does continue with the execution correctly).
Is there a way I can tell PHP to not print out those Warning messages for
!$var cases?
I relize there is the isset($var) option, but this is not an option in
some cases.
Thanks for any help!
Nick
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