An example:
<?
$MyVar = "Contents";
$$MyVar = "Will it work?";
echo "\$Contents = $Contents\n";
?>
This will echo
$Contents = Will it work?
HTH,
Fernando Madruga
-----Original Message-----
From: Michael Rudel [mailto:[EMAIL PROTECTED]]
Sent: quarta-feira, 21 de Março de 2001 14:14
To: 'Will Degener'; 'Php-Windows (E-mail)'
Subject: RE: [PHP-WIN] Naming Variables Based on Variable Content
Sure,
$MyVar = "Contents";
$$MyVar equals $Contents.
Taken from the Manual, Language Reference (which everyone should read first
=8),
Chapter 7: Variables / Variable Variables
Greetinx,
Mike
Michael Rudel
- Web-Development, Systemadministration -
_______________________________________________________________
Suchtreffer AG
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Germany
fon: +49-(0)7531-89207-17
fax: +49-(0)7531-89207-13
e-mail: mailto:[EMAIL PROTECTED]
internet: http://www.suchtreffer.de
_______________________________________________________________
> -----Original Message-----
> From: Will Degener [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, March 21, 2001 3:01 PM
> To: Php-Windows (E-mail)
> Subject: [PHP-WIN] Naming Variables Based on Variable Content
>
>
> Any ideas if this is possible and if so how ???
> Thanks in advance. - Will
>
> If I have a variable :
>
> $MyVar = "Contents";
>
> Can I create a variable at "runtime" that has a name based on
> the contents
> of $MyVar ?
> eg
>
> $Contents
>
>
>
>
>
>
>
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