Perhaps I was unclear...I actually _want_ to modify the copy, that's
why I made a copy, to preserve the original. My point was that this
doesn't seem to create a valid copy of the original array:
$new_array = $first_array["second array"];
Operations on $new_array seem to fail, because it isn't an array.
Using a reference would modify the original, and I don't want to do
that.
Doug
| -----Original Message-----
| From: Ernest E Vogelsinger [mailto:[EMAIL PROTECTED]]
| Sent: Saturday, March 03, 2001 7:17 PM
| To: Doug Brewer
| Cc: [EMAIL PROTECTED]
| Subject: Re: [PHP-WIN] pulling arrays from nested arrays?
|
|
| At 01:21 04.03.2001, Doug Brewer said:
| --------------------[snip]--------------------
| >$new_array = $first_array["second array"]; # what's wrong
| with this?
|
| this is a copy of $first_array["second array"].
|
| >while(list($this, $that) = each($new_array)) {
| > # doesn't work!
| >}
|
| this modifies the copy!
|
| After applying the modifications, do
| $first_array["second array"] = $new_array;
| to replace the original with the modified contents.
|
| Usually you would use references to arrays to handle this,
| but I haven't
| found a way yet to get list() to return references instead
| of copies...
|
|
| ...ebird
|
| >O Ernest E. Vogelsinger
| (\) http://www.1-at-web.at/
| ^ ICQ# 13394035
|
|
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