Dear all, I want to populate the value of a include file in a variable. Is it possible?
e.g. my php page is http://xyz.com/abc.php and suppose the code is like the following <?php include('http://www.yahoo.com'); ?> the out put of above code is : It prints the same output if browser has requested http://www.yahoo.com I want to store the this out put in a variable of a php page and then give print command <?php $x= include('http://www.yahoo.com'); //upto this moment no out put print $x; //now out put should be displayed IS IT POSSIBLE, IF YES THEN HOW? Thank you, Mukesh Kumar ?> ------------------------ Yahoo! Groups Sponsor --------------------~--> Get Bzzzy! (real tools to help you find a job). Welcome to the Sweet Life. http://us.click.yahoo.com/A77XvD/vlQLAA/TtwFAA/HKFolB/TM --------------------------------------------------------------------~-> Community email addresses: Post message: php-list@yahoogroups.com Subscribe: [EMAIL PROTECTED] Unsubscribe: [EMAIL PROTECTED] List owner: [EMAIL PROTECTED] Shortcut URL to this page: http://groups.yahoo.com/group/php-list Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/php-list/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
