Mike, I've run into similar concerns while debugging my own php code; I'm relatively new to php, so can't offer much help as to 'what changed as of which version', but...
One thing I have run into already while debugging: php parses the _entire_ script before attempting to execute it. So, as I understand it, 'traditional' methods of passing an 'echo' command, for example, to see how far the program has 'stepped' may give you misleading results (as in no results at all!) I _would_ suggest you turn on all the debug message options in your php.ini file while trying to sort this out, though... Please let me know how you sort this out - I am running into errors, too, with a similar - very simple - if/else construct. Lou > Hello. > I've installed 4.2.3 on Apache 1.3.26 running on an Sun Ultra 1 with Solaris > 9. > > I have a script I wrote a while back that has worked fine on PHP 4.0.5 on my > current server. The script displays images on a web page. I build a pop-up > list of all the images in the current directory and have a "show" button > which sends a url thusly: > > http://vortac.aviate.org/53sf/show.php?thePhoto=photo1.jpg > > The script starts by checking whether the argument exists, then passes the > name of the photo for processing: > > if( $thePhoto ) { > LoadImageData(); > DisplayPhoto( "$thePhoto" ); > } else { > LoadImageData(); > > if( count($photos) > 0 ) { > DisplayPhoto( "$photos[0]" ); > } else { > PrintError( "Viewer error! can't load photos." ); > } > } > > This works fine on 4.0.5, but is broken on 4.2.3! I can't seem to figure out > what is going on. I threw phpinfo in the script to make sure that the arg is > being passed to php, and it shows that it is, yet the script never gets past > the test: if( $thePhoto). > > I put a call to phpinfo() before the LoadImageData() function just to see if > the script even gets that far: > > if( $thePhoto ) { > phpinfo(); > LoadImageData(); > DisplayPhoto( "$thePhoto" ); > } else { > LoadImageData(); > > if( count($photos) > 0 ) { > DisplayPhoto( "$photos[0]" ); > } else { > PrintError( "Viewer error! can't load photos." ); > } > } > > I never see the phpinfo dump. To test this I entered > "show.php?thePhoto=test.jpg" in a browser (with the correct url preceeding > the script name). So, it appears PHP is never parsing the argv, or something > major has changed between 4.05 and 4.23 where my test has to be re-written. > > I'd appreciate some input. > > Thanks. > > -- > Mike Carter > Pilot/Programmer > [EMAIL PROTECTED] -- PHP Install Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
