Re: [PHP] fopen

[Mat Harris]

that example code is trying to print out data which refers to the 
integer filehandle of the fopen. To get data out of the file that you 
have opened, you will need to read() it in.

John Taylor-Johnston wrote:
#http://www.php.net/manual/en/function.fopen.php

$contents = fopen ("/home/pathto/file.txt", "r");

if ($contents){echo"<textarea>$contents</textarea>";}
else{echo "no contents there";}
Questions:
What is the use of "@fopen"?
Does anyone see a better way?



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