AW: [PHP] Re: How to use the fields of an array as individual parameter for a function

[Christian Bartels]

Well, Tom Rogers already posted this solution and it works great:

                  $num = count($params);
                        $vars = '$object = new foo2(';
                        if($num > 0) {
                          $i = 0;
                          foreach($params as $var){
                            $vars .= ($i > 0)? ',':'';
                            $vars .= (is_string($var))? "'".$var."'" : $var;
                            $i ++;
                          }
                        }
                        $vars .= ');';
                        
                        eval($vars);


---
Gruß 
CB

-----Ursprüngliche Nachricht-----
Von: Dimitris Kossikidis [mailto:[EMAIL PROTECTED] 
Gesendet: Dienstag, 4. März 2003 12:18
An: [EMAIL PROTECTED]
Betreff: [PHP] Re: How to use the fields of an array as individual parameter
for a function


I suppose that argc & argv variables should be supported in future releases
of php. At this time only cgi php supports this feature. Am i wrong?

"Christian Bartels" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
Hello!

I'm new here on the list. I hope you can help me! :)

I have a function foo1 which has a parameter $params. In the function i want
to pass $params to another function foo2. if $params is an array the
elements should be passed to foo2 as individual parameters. Is this
possible? How do i do that?

Example:

function foo1($params) {
  if (is_array($params)) {
    $object = new foo2(GET THE ELEMENTS OF $params AS INDIVIDUAL PARAMETERS
HERE);
  } else {
    $object = new foo2($params);
  }
}

So when this is called:
foo1(array('blue', 'red', 'green'));

In foo1 foo2 should be called like this:
foo2('blue', 'red', 'green');

Is this possible?

Thanks for any help!

(sorry about my english ;-))

---
CB



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