Hi,
yes in fact it worked...I also had the $numrows with wrong mysql command, it should be mysql_num_rows() instead of the mysql_fetch_rows(). Thx Ernest
But now that this is working, i have another big problem...my $drop_down_list isn't assuming the value of the shown option...right here on the below part
******** for ($i = 0; $i < $num; $i++) { $aviao = mysql_result($resultaviao, $i, "aviao"); $sk = mysql_result($resultaviao, $i, "sk"); $drop_down_list .= "<optionvalue=$aviao>$aviao</option>"; } **********
So he isn't getting the data from DB. He displays all records on DB available at aviao field, but he is not making the correct mysql query...
For debugging:
- please show us the query if you believe it is wrong (echo $query;).
- if you think something goes wrong at the mysql side, also do echo mysql_error(); after the mysql_query line, to get the mysql error.
- echo $num .
Also have a look at the html source to see whether it has the right options but another error than you expected.
$drop_down_list .= "<optionvalue=$aviao>$aviao</option>";Put some quotes around the tag value for just in case the $aviao has a space in it:
$drop_down_list .= "<optionvalue=\"$aviao\">$aviao</option>";
FInally, why do you extract $sk when you do not use it?
Anyone knows why?
----- Original Message ----- From: "Ernest E Vogelsinger" <[EMAIL PROTECTED]> To: "Miguel Brás" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Monday, February 24, 2003 9:45 AM Subject: Re: [PHP] What is wrong with this?
At 10:37 24.02.2003, Miguel Brás said: --------------------[snip]-------------------- >//logical request >if ($nome) { >$sql="aviao = '$nome' "; >} >if ($code) { >$sql="code = '$code' "; >} > $query = "SELECT * FROM ssr WHERE"; > $query .= $sql; --------------------[snip]--------------------
Hi,
I've copied only the relevant lines of your program.
The issue here is that your string concatenation results in SELECT * FROM ssr WHEREaviao = 'Airbus'
Note the missing space after "WHERE". Your code should better read $query = "SELECT * FROM ssr WHERE "; $query .= $sql; Have an eye on the added blank after WHERE.
HTH,
-- >O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
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