for ($i=0; i <$count;$i++) {
You left the $ out. It's looking for a constant named i, which doesn't exist.
Janyne Kizer wrote:
I'm not sure. It sits and spins. If I go to view -> source that
doesn't yield any additional information. We are trying to build the
array and then use in_array to handle the data appropriately.
Rick Emery wrote:
what times out? The query?
rick
"People will forget what you said. People will forget what you did.
But people will never forget how you made them feel."
----- Original Message -----
From: "Janyne Kizer" <[EMAIL PROTECTED]>
To: "Rick Emery" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, February 17, 2003 9:51 AM
Subject: Re: [PHP] Problem creating array from MySql query
No error. It just times out.
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