This statement doesnt look right to me.
if(isset($_POST['userid']) && isset($_POST['pword'])){
$_SESSION['user'] = $_POST['userid'];
$_SESSION['password'] = $_POST['pword'];
}
the if should be:
if ((statement)&&(statement))
{
}
so:
if ((isset($_POST['userid'])) && (isset($_POST['pword'])))
{
$_SESSION['user'] = $_POST['userid'];
$_SESSION['password'] = $_POST['pword'];
}
That should work.
"Willie G" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Tom,
>
> I do have a session_start() in both files, but it does not seem to help.
>
> - Larry
>
> -----Original Message-----
> From: Tom Rogers [mailto:[EMAIL PROTECTED]]
> Sent: Sunday, January 12, 2003 11:36 AM
> To: Willie G
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP] SESSION variable to pass login ID
>
>
> Hi,
>
> Monday, January 13, 2003, 1:04:49 AM, you wrote:
> WG> Hi,
>
> WG> I have been trying to solve the problem of using session variables,
but
> I
> WG> have not had any luck. What I want to do is simple, I want to set my
> userid
> WG> and password in a login screen and use it later (in another php form)
to
> log
> WG> into the database.
>
> WG> In my login PHP file I have the following:
>
> WG> if(isset($_POST['userid']) && isset($_POST['pword'])){
> WG> $_SESSION['user'] = $_POST['userid'];
> WG> $_SESSION['password'] = $_POST['pword'];
> WG> }
>
> WG> In my connect to database PHP file I have:
>
> WG> if(isset($_SESSION['user'])){
> WG> $user=$_SESSION['user'];
> WG> echo "Print $user";
> WG> }else{
> WG> echo "Print Missing User";
> WG> }
>
>
> WG> The message I always get is "Print Missing User", so I must assume the
> WG> global variable is not working. Can anyone help me out here?
>
> WG> Thanks,
> WG> Larry
>
> Make sure you have session_start() at the begining of the second file.
>
> --
> regards,
> Tom
>
>
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>
>
>
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