print "<img src=\" " . $row["banner_nombre"] . " \">";
You can get rid of the [ print "<a href=\" " . $row["banner_nombre"] . " \">"; ] and the [ print "</a>"; ] code.
This will display the image. I misunderstood before and thought you wanted the link to go to a page. But for displaying an image. The above code should do the trick.
Joe
On Wednesday, January 1, 2003, at 03:10 PM, Ezequiel Sapoznik wrote:
Thanks for your help!
I try, but if you check at http://www.historiadelpais.com.ar/test.php, you
can see that I still have the link but what I need is that the php shows the
jpg image.
Thanks!
Ezequiel
"Joe Lomoglio" <[EMAIL PROTECTED]> escribió en el mensaje
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
On Wednesday, January 1, 2003, at 02:06 PM, Ezequiel Sapoznik wrote:print($row["banner_nombre"] ."<br>\n");Try this: print "<a href=\" " . $row["banner_nombre"] . " \">"; print ($row["banner_nombre"] ."<br>\n"); print "</a>"; Joe-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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