Simple:
while($rows[]=mysql_fetch_array($res)) {}
($res is a mysql result resource)
Beauford.2002 wrote:
Thanks for the info, but maybe I didn't give enough info.
I have a mysql database with up to 10 rows and 5 fields in each row.. I have
been reading up on some of the array functions, but haven't been able to get
anything to work.
TIA
----- Original Message -----
From: "Weston Houghton" <[EMAIL PROTECTED]>
To: "Beauford.2002" <[EMAIL PROTECTED]>
Cc: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, December 26, 2002 6:19 PM
Subject: Re: [PHP] Nested Arrays
Sure... for the longwinded approach, just do this:
$row1 = array("col1", "col2", "col3", ...);
$row2 = array("col1", "col2", "col3", ...);
$row3 = array("col1", "col2", "col3", ...);
$row4 = array("col1", "col2", "col3", ...);
$row5 = array("col1", "col2", "col3", ...);
$main_array = array($row1, $row2, $row3, $row4, $row5);
Obviously these could include key-value pairs in the arrays as well.
Then to prove it to yourself:
print_r($main_array);
Cheers,
Wes
On Thursday, December 26, 2002, at 06:14 PM, Beauford.2002 wrote:
Hi,
Is there anyway to do a nested array, I have looked at the various
array
functions and can't figure this out (if possible).
I want to be able to put each field of a row into an array, and then
put
that entire row and into another array.
so when I display it, I would have:
row1 - col1 col2 col3 col4 col5
row2 - col1 col2 col3 col4 col5
row3 - col1 col2 col3 col4 col5
row4 - col1 col2 col3 col4 col5
row5 - col1 col2 col3 col4 col5
etc. (depending on how many rows there are).
TIA
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