22 Manopohuji wrote:
hi, i'm running into some weird behavior with php references. i
distilled it down to some test code below:
<?php
$array = array( 'name' => 'dean' );
$var1['arrayref'] = & $array;
$var2 = $var1;
echo "var1:\n";
print_r( $var1 );
echo "var2:\n";
print_r( $var2 );
$var1['arrayref'] = NULL;
echo "var1:\n";
print_r( $var1 );
echo "var2:\n";
print_r( $var2 );
?>
it seems that setting a hash key to a reference to something, and then
repointing that key to NULL, apparently sets the original 'something' to
NULL instead of just 'repointing' the hash key! am i missing something
obvious here, or is this behavior not what you'd normally expect? i
wrote similar code in perl, and it behaved as i expected: the second
hash still pointed to the original target (i am almost certain c/c++ and
java also behave this way). so what is going on with php? does anyone
know how to get it to do what i want it to do -- i.e., merely unset the
key mapping of one of the hashes, leaving the other hash still pointing
at the target? thansk for any insight you might be able to give!
xomina
Have a look at: http://www.php.net/manual/en/language.references.php
<quote>They are not like C pointers, they are symbol table aliases.</quote>
Instead of:
$var1['arrayref'] = NULL;
use:
unset($var1['arrayref']);
Peter
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