Re: [PHP] 2 dates, difference in days AARGH!!

[Curtis Gordon]

I have made those changes, thank you (I even read the integers required thing but for some reason didn't register it).
Here is what I have now. Working with Dec 25, 2002 (a difference that should be 14 days).

<?$maturity_date = mktime (0,0,0,$mday_row[3],$mday_row[2],$mday_row[5]);?>
<?$today = getdate();?>
<?$now_date = mktime (0,0,0,$today['mon'],$today['mday'],$today['year']);?>
<?$difference_date = ($maturity_date - $now_date);?>
<?$difference_days = ($difference_date / 86400);?>
difference in days: <?print $difference_days;?>

AND IT WORKS!!!!

Thank you Chris you have saved, my hairline, my marriage, and my sanity!


Chris Wesley wrote:

Oh, and $today['wday'] ... that's the day of the week. I'm almost
positive you want the day of the month: $today['mday'].

hth,
~Chris

On Wed, 11 Dec 2002, Chris Wesley wrote:

On Wed, 11 Dec 2002, Curtis Gordon wrote:

future date:
<?$maturity_date = mktime (0,0,0,$mday_row[3],$mday_row[2],$mday_row[5]);?>
current date:
<?$today = getdate();?>
<?$now_date = mktime
(0,0,0,$today['month'],$today['wday'],$today['year']);?>

$today['month'] is text, ie. "December", and mktime() requires all
integer arguments. If you use $today['mon'] instead, it seems like
you'll get what you want.

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