You simply need the absolute value of the difference. So taking Stephen's
example below..
$total = 0;
foreach( $_POST['nums'] as $number )
{
$total -= $number; // if users inputs 5 as first value result equals -5
$total = abs($total); // result now equals 5
}
----- Original Message -----
From: "Stephen" <[EMAIL PROTECTED]>
To: "Chris Wesley" <[EMAIL PROTECTED]>
Cc: "PHP List" <[EMAIL PROTECTED]>
Sent: Thursday, December 05, 2002 12:33 PM
Subject: Re: [PHP] Looping Addition
> Continuing this even more...how would I use this same method only to
> subtract?
>
> What I'm doing right now would result in the following sitution.
>
> The user types in 5 as their first number. The second number is 4. Instead
> of returnin 1, it returns -9. It's subtracting the first number from 0,
then
> taking 4 and subtracting that from -5. How can I fix this keeping in mind
> the user may type in more then two numbers?
>
>
> ----- Original Message -----
> From: "Chris Wesley" <[EMAIL PROTECTED]>
> To: "PHP List" <[EMAIL PROTECTED]>
> Cc: "Stephen" <[EMAIL PROTECTED]>
> Sent: Wednesday, December 04, 2002 8:42 PM
> Subject: Re: [PHP] Looping Addition
>
>
> > On Wed, 4 Dec 2002, Stephen wrote:
> > > This is only a snippet, there is more to it but for simplicities
sake...
> > > Then I calculate it. My question is, how would I loop the adding? I
hope
> you
> > > understand this now...
> >
> > Ah!, I think I understand better now. You want to add num1, num2, num3,
> > ... numN, which are inputs from the second form in your sequence.
Gotcha.
> >
> > If you name /all/ the form elements as "nums[]" instead of individually
as
> > "num${current}", the numbers put into the form will all be accessible in
> > one array to the PHP script that does the adding. Then you can just
loop
> > over the array of numbers.
> >
> > In your second form, change this:
> > "<input name="num<?php echo $current; ?>" type="text" id="vars"
value="0"
> > size="25">"
> >
> > To this:
> > "<input name="nums[]" type="text" id="vars" value="0" size="25">
> >
> > Then in the script that adds the numbers:
> > $total = 0;
> > foreach( $_POST['nums'] as $number ){
> > $total += $number;
> > }
> >
> > Hopefully I understood your problem this time! Let me know if I missed
> > again.
> > g.luck,
> > ~Chris
> >
> >
>
>
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