-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
2 fonction for that ;)
written specially for the same pb as you ;)
// transformation de la date jj/mm/aaaa -> aaaa-mm-jj
function modate ( $date )
{ $inter= split("/",$date) ;
$date=$inter[2]."-".$inter[1]."-".$inter[0] ;
return $date ;
}
// transformation de la date aaaa-mm-jj -> jj/mm/aaaa
function revmodate( $date )
{ $inter= split("-",$date) ;
$date=$inter[2]."/".$inter[1]."/".$inter[0] ;
return $date ;
}
Le Mardi 19 Novembre 2002 15:10, Edward Peloke a ��crit :
> I am pulling from a datetime field in mysql. The actual data looks like
> this: 2002-11-30 00:00:00 When I output the data to the page, I want it to
> appear as 11/30/2002. I want to use a php date format. I do not want it
> formatted as it comes out of the db. But date("m/d/y", $myrow[departdate])
> returns 12/31/69. How can I do this?
>
> THanks,
> Eddie
- --
__________
/ Matthieu Le Corre
| Service Informatique
| ____________________
| Inspection Academique de la Sarthe
| 72000 LE MANS
| ____________________________
| Tel : 02 43 61 58 91
| Mail : [EMAIL PROTECTED]
\____________________________________
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.0.7 (GNU/Linux)
iD8DBQE921i5iQG6YxCcev4RAu1jAJ0UFm1XAp7C8zKeOPc/CEA32jZpdgCfReBY
3uhaeYd614pugiecRDDCYOM=
=7f9l
-----END PGP SIGNATURE-----
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
