On Mon, 4 Nov 2002, 1LT John W. Holmes wrote:

>Do you have file uploads enabled in php.ini?

No, sorry. I changed that and all worked fine. 

I wonder why that is not mentioned on the section
of uploads of the PHP documentation.

Thanks a lot.

---sram

>---John Holmes...
>
>----- Original Message -----
>From: "Salvador Ramirez" <[EMAIL PROTECTED]>
>To: "1LT John W. Holmes" <[EMAIL PROTECTED]>
>Cc: "PHP General" <[EMAIL PROTECTED]>
>Sent: Monday, November 04, 2002 4:04 PM
>Subject: Re: [PHP] $_FILES
>
>
>> On Mon, 4 Nov 2002, 1LT John W. Holmes wrote:
>>
>> >How about just
>> >
>> >print_r($_FILES);
>> >
>> >Does that return anything?
>>
>> It just return the same as before, i.e. "Array ( )"
>>
>> ---sram
>>
>> >---John Holmes...
>> >
>> >----- Original Message -----
>> >From: "Salvador Ramirez" <[EMAIL PROTECTED]>
>> >To: "PHP General" <[EMAIL PROTECTED]>
>> >Sent: Monday, November 04, 2002 3:50 PM
>> >Subject: [PHP] $_FILES
>> >
>> >
>> >> Hi,
>> >>
>> >>   I hope somebody could help me with a problem I have with the $_FILES
>> >> variable.
>> >>
>> >>   I'm trying to make a PHP script which could have access to an
>uploaded
>> >> remote file. The piece of HTML is:
>> >>
>> >> ----------------
>> >> <html>
>> >> <body>
>> >>
>> >> <form action="ll.php" method="post" enctype="multipart/form-data">
>> >>   <input name="userfile" size=48 type="file">
>> >>   <input type="submit" name="attach" value="Add"><br>
>> >> </form>
>> >>
>> >> </body>
>> >> </html>
>> >> ----------------
>> >>
>> >> and the ll.php script is:
>> >>
>> >> ----------------
>> >> <?php
>> >>   printf("file=(%s)<br>", $_FILES['userfile']['name']);
>> >>   print_r(array_values($_FILES));
>> >>   phpinfo();
>> >> ?>
>> >> ----------------
>> >>
>> >> but the variable $_FILES is not set at all, because the printf doesn't
>> >> print the name of the uploaded file nor the second line, the print_r()
>> >> print anything for that array variable.
>> >> So the question is: what could be happening that the variable $_FILES
>is
>> >> not set?
>> >>
>> >> The phpinfo() function returns PHP 4.2.3, and I compiled it with the
>> >> following configure line:
>> >>
>> >> './configure' '--with-mysql'
>> >> '--with-apxs=/server/www/apache-1.3.26/bin/apxs' '--with-imap'
>> >> '--with-imap-ssl' '--enable-track-vars' '--enable-dbase'
>> >> '--with-pgsql=/server/postgresql'
>> >>
>> >> over an apache 1.3.26.
>> >>
>> >> Any help will be very appreciated.
>> >>
>> >> Thanks in advance.
>> >>
>> >> ---sram
>> >>      "Don't listen to what I say; listen to what I mean!" --Feynman
>> >> Salvador Ramirez Flandes        PROFC, Universidad de Concepcion, CHILE
>> >> http://www.profc.udec.cl/~sram                mailto:sram@;profc.udec.cl
>> >>
>> >>
>> >>
>> >> --
>> >> PHP General Mailing List (http://www.php.net/)
>> >> To unsubscribe, visit: http://www.php.net/unsub.php
>> >>
>> >
>>
>
>


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