Stephen,
after your line:
>$query = "SELECT * FROM orders WHERE orderid = '$orderid'";
you should add:
mysql_query($query);
in your code line you've just set your variable--you haven't asked mysql to
do anything.
Hope this helps.
Hugh
----- Original Message -----
From: "Steve Jackson" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Monday, November 04, 2002 12:42 AM
Subject: [PHP] Address array?
> I want to display an address from my database based on an orderid. Where
> am I going wrong? I am still unsure how Php interacts with mySQL but am
> I right in assuming it should be an array?
>
> My code...
>
> function get_shipping_address($address_array)
> {
> $conn = db_connect();
> $orderid = get_order_id($orderid);
> $query = "SELECT * FROM orders WHERE orderid = '$orderid'";
> $row = mysql_fetch_array($query);
> foreach ($address_array as $row)
> {
> $ship_name = $row["ship_name"];
> $ship_address = $row["ship_address"];
> $ship_city = $row["ship_city"];
> $ship_zip = $row["ship_zip"];
> $ship_country = $row["ship_country"];
> }
> }
>
> Steve Jackson
> Web Developer
> Viola Systems Ltd.
> http://www.violasystems.com
> [EMAIL PROTECTED]
> Mobile +358 50 343 5159
>
>
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