If I try that I get a wrong parameter count error.
Ed On Thu, 31 Oct 2002, Jay Blanchard wrote: > [snip] > I using number_format where I need to turn a number say "123456789" into > "123,456,789" and it works just fine. I also need it to strip the decimal > out if someone enters it. I.E "123456.00" would become "123,456" > > the command I'm using right now is: > > number_format($number, ","); > > If I enter "123456.00" it comes out as "123". Did I miss something? > [/snip] > > You're missing an attribute, try > > number_format($number, '', ','); > > HTH! > > Jay > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
