Ok, here is my solution: I wanted this to be as self contained as possible:
function clean() { /* get name of session & find session id */ $name = ini_get('session.name'); $sessid = ( !$_COOKIE[$name] ? ( !$_GET[$name] ? ( !$_POST[$name] ? false : $_POST[$name] ) : $_GET[$name] ) : $_COOKIE[$name] ); /* run query now to see if sesion is expired, if yes */ unset( $_COOKIE[$name] ); unset( $_GET[$name] ); unset( $_POST[$name] ); unset( $_REQUEST[$name] ); } clean(); session_start(); Since _COOKIE/etc needs to be UNSET before session_start is called and re-calling session_start does sqat, the above code (not all of it but general idea) 'finds' the session id (session_id() has no effect until session_start is called) and tests to see if it's expired, if so, it 'kills' all possible locations for session_start() to find an id. *simple*... (or something like that) -js Chris Shiflett wrote: > Yeah, John hinted at the answer there. > > You just need to make the session ID go away prior to starting the > session . Just unset it or set it to the empty string or whatever you > want to do. > > It is probably either $_COOKIE["PHPSESSID"] or $_GET["PHPSESSID"]. > > Chris > > John W. Holmes wrote: > >>> "Simple" question. If a users session expires or has timed out, how do >>> >>> I 'force' php to generate a new sessionId? >>> >> >> Session_start() ?? >> >> If there isn't a session id present, it'll create one. >> >> ---John Holmes... >> > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php