In article <[EMAIL PROTECTED]>, [EMAIL PROTECTED] says... > Anthony Ritter wrote: > > I am trying to access a website that has tab delimited data and use > > PHP to open the file, read from the > > file for output. > > > > I'd like to then place this data into an array, loop through the > > array and output only the next to last record. > > > > Is there any way to loop through the following records - there are 96 > > - and keep only the *next to last last one* (which would be the most > > current record) before hitting EOF. > > > > They store the records every 15 minutes for a 24 hour span. > > > > I do not need all 96 records - only the most current - or - next to > > last - record. > > Read the file with the file function (http://www.php.net/file). This will > give you an array, with each element representing a line in the original > file. > Pop the last element away (http://www.php.net/array_pop) twice. The second > time you do this, store the element you will gain (pop will return the > element it popped). There you have it... > > In code: > > <? > $content = file( > 'http://waterdata.usgs.gov/ny/nwis/uv?format=rdb&period=1&site_no=01420500' > ); > array_pop( $content ); > $current = array_pop( $content ); > ?>
OK - this is a fine candidate for 'how many ways can it be done?'. My contribution [NB untested]: <? $content = file( 'http://waterdata.usgs.gov/ny/nwis/uv?format=rdb&period=1&site_no=01420500 '); $current = $content{count($content)-2}; Use count to find the number of elements and use count-2 to select the second-to-last element. Recall that the first element is [0]. Cheers -- David Robley Temporary Kiwi! Quod subigo farinam -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
