I'm having the error again this time on my webserver. I have it set as a global variable but it's not working. It can be found at http://mom.melchior.us. Type in test for the username and password. Why???
Thanks, Stephen http://www.melchior.us http://php.melchior.us :: -----Original Message----- :: From: debbie_dyer [mailto:[EMAIL PROTECTED]] :: Sent: Saturday, September 28, 2002 6:03 PM :: To: [EMAIL PROTECTED] :: Subject: Re: [PHP] Member's Area Script :: :: :: :: $conn = $main; <- that line is the problem - you cant use :: global vars inside functions without declaring them as global :: :: ----- Original Message ----- :: From: "Stephen Craton" <[EMAIL PROTECTED]> :: To: <[EMAIL PROTECTED]> :: Sent: Saturday, September 28, 2002 11:49 PM :: Subject: [PHP] Member's Area Script :: :: :: > Hello again, :: > :: > I'm trying to write a script that has a member's area in :: it. So far :: > I've been able to successfully validate only one username :: and only one :: > password but now I'm going big and trying to compare it :: with a table :: > in my MySQL database. Everything goes nice and smooth :: until I actually :: > try and enter in my username and password. I type it in, copy and :: > paste, whaetever and it tells me the error I wanted it to say "The :: > username and password is not a good combo." I've copied :: and pasted the :: > username and password from the database directly yet it :: still gives me :: > this error. Here's my code for the login() function that :: logs the user :: > in: :: > :: > function login($username, $password) :: > { :: > $conn = $main; :: > if (!$conn) :: > return 0; :: > :: > $result = mysql_query("select * from user :: > where username='$username' :: > and passwd = '$password'"); :: > if (!$result) :: > return 0; :: > :: > if (mysql_num_rows($result)>0) :: > return 1; :: > else :: > return 0; :: > } :: > :: > Here's the code for the part that calls the login() function: :: > :: > if(login($user, $pass)) :: > { :: > $valid_user = $user; :: > session_register("valid_user"); :: > } :: > else :: > { :: > echo "<font face='Arial, Helvetica, sans-serif' :: > size='3'><center><b>You supplied an invalid username and password :: > combo. Try again please.</b></center>"; exit; :: > } :: > :: > And here's the part that connects to the database: :: > :: > <?php :: > # FileName="Connection_php_mysql.htm" :: > # Type="MYSQL" :: > # HTTP="true" :: > $hostname_main = "localhost"; :: > $database_main = "mom"; :: > $username_main = "root"; :: > $password_main = ""; :: > $main = mysql_pconnect($hostname_main, $username_main, :: $password_main) :: > or die(mysql_error()); ?> :: > :: > Does anyone see why it's doing this to me? Please help!! :: > :: > Thanks, :: > Stephen :: > http://www.melchior.us :: > http://php.melchior.us :: > :: > :: > :: > -- :: > PHP General Mailing List (http://www.php.net/) :: > To unsubscribe, visit: http://www.php.net/unsub.php :: > :: :: :: -- :: PHP General Mailing List (http://www.php.net/) :: To unsubscribe, visit: http://www.php.net/unsub.php :: :: -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
