There seems to be a print-error in this book. It's missing a '$'
This line:
> if (compteur == 1) {
should be:
> if ($compteur == 1) {
Sascha
Am Montag, 30. September 2002 01:52 schrieb Voisine:
> Hello,
>
> I'm learning PHP from a book "PHP for newbie writen in French" and I
> have an error on one of the exemple. Undifined constant 'compteur' on
> line 15 which is :
> if (compteur == 1) {
>
> What I'm doing wrong? This is the script
>
> <?php
> include("config.inc.php");
> $query = "SELECT * FROM Type ORDER BY animalType";
> $result = mysql_query($query) or die ("Exécution de la sélection
> impossible");
>
> echo "<h1 align='center'>Catalogue</h1><p><h3>Quel type d'animal
> cherchez-vous ?</h3>\n";
> echo "<form action='montre_animaux.php' method='post'>\n";
> echo "<table cellpadding='5' border='1'>";
> $compteur = 1;
> while ($ligne = mysql_fetch_array($result)) {
> extract($ligne);
> echo "<tr><td valign='top' width='15%'>";
> echo "<input type='radio' name='interet' value='$animalType'>";
> if (compteur == 1) {
> echo "checked";
> }
> echo "<font
> size='+1'><b>$animalType</b></font></td><td>$typeDescription</td></tr>";
>
> $compteur++;
> }
> echo "</table>";
> echo "<p><input type='submit' name='submit' value='Faites votre
> choix'></form>";
> ?>
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