On 25-Sep-2002 Daren Cotter wrote: > Jason, > > That's exactly what I'm trying to do, and it's not > working: > > My Script: >#!/usr/bin/php -f > <?php > $test = $argv[1]; > print $test; > $demo = "This Works"; > print $demo; > ?> > > Running: > ./test.php blah > > Yiels only "This Works", but not "blah". > > I'm using version 4.0.6 >
try var_dump($argv); var_dump($GLOBALS); > > --- Jason Young <[EMAIL PROTECTED]> wrote: >> I can't say I'm really too familiar with the php >> commandline.. >> >> You're using /usr/bin/php (or equivalent) and >> attempting to use your >> exec() that way? >> >> If you do 'php -?' you'll get a list of commands >> that you can use, and I >> don't see a way to pass cmdline arguments as >> variables.. >> >> Having said that, I Just went and looked further >> into it.. if I make a >> test script, and at the top I put: >> $hi = $argv[1]; >> >> then $hi becomes whatever you've specified as the >> first argument.. I'm >> assuming this is what you want? >> >> To clarify: >> phpfile.php contains: >> <? >> $hi = $argv[1]; >> echo $hi; >> ?> >> >> Running the command "php -f phpfile.php test" >> returns "test" >> >> Does this help at all?? >> >> -Jason >> >> Daren Cotter wrote: >> > Jason, >> > >> > I'm not using a web script any longer, I'm using >> > command-line (I determined that it is installed on >> the >> > server). >> > >> > I read about $argc and $argv, but when I call the >> > script passing two arguments, both $argc and $argv >> are >> > blank. Is this a php.ini setting I need to change >> or >> > somethign? >> > >> > --- Jason Young <[EMAIL PROTECTED]> wrote: >> > >> >>Sorry to butt in :) >> >> >> >>Arguments to web scripts are done in the format: >> >>page.php?arg1=data1&arg2=data2 >> >> >> >>So you would use that full string as the lynx >> path. >> >> >> >>Hope this helps :) >> >>-Jason >> >> >> >>Daren Cotter wrote: >> >> >> >>>Thanks for the info Chris, it works! >> >>> >> >>>How do I pass arguments to the script? I'm >> >> >> >>assuming >> >> >> >>>it'd just be: >> >>> >> >>>test.php arg1 arg2 >> >>> >> >>>The stuff I've read says $argc should be the >> count >> >> >> >>of >> >> >> >>>the # of arguments, and $argv should be an array >> >>>holding them...but when I do a simple: >> >>>print "# of Arguments: $argc\n"; >> >>>It prints nothing, not even 0 >> >>> >> >>> >> >>>--- Chris Hewitt <[EMAIL PROTECTED]> >> >> >> >>wrote: >> >> >> >>>>>On Wed, 25 Sep 2002, Daren Cotter wrote: >> >>>>> >> >>>>> >> >>>>> >> >>>>>>My problem, is that I absolutely NEED to run a >> >>>>> >> >>PHP >> >> >> >>>>>>script using crontab. The script needs to send >> >>>>>>numerous queries to a database every hour. Is >> >>>>> >> >>>>there >> >>>> >> >>>> >> >>>>>>any way I can accomplish this, directly or >> >>>>> >> >>>>indirectly? >> >>>> >> >>>>Are you sure its not already there? Commonly in >> >>>>/usr/bin. Try a "which >> >>>>php" and see if it finds anything? >> >>>> >> >>>>HTH >> >>>>Chris >> >>>> >> >>> >> >>> >> >>> >> >>>>__________________________________________________ >> >>>Do you Yahoo!? >> >>>New DSL Internet Access from SBC & Yahoo! >> >>>http://sbc.yahoo.com >> >> >> >> >> >>-- >> >>PHP General Mailing List (http://www.php.net/) >> >>To unsubscribe, visit: >> http://www.php.net/unsub.php >> >> >> > >> > >> > >> > __________________________________________________ >> > Do you Yahoo!? >> > New DSL Internet Access from SBC & Yahoo! >> > http://sbc.yahoo.com >> >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> > > > __________________________________________________ > Do you Yahoo!? > New DSL Internet Access from SBC & Yahoo! > http://sbc.yahoo.com > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- Don Read [EMAIL PROTECTED] -- "Beer is proof that God loves us and wants us to be happy." -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
