Jason,

I'm not using a web script any longer, I'm using
command-line (I determined that it is installed on the
server).

I read about $argc and $argv, but when I call the
script passing two arguments, both $argc and $argv are
blank. Is this a php.ini setting I need to change or
somethign?

--- Jason Young <[EMAIL PROTECTED]> wrote:
> Sorry to butt in :)
> 
> Arguments to web scripts are done in the format:
> page.php?arg1=data1&arg2=data2
> 
> So you would use that full string as the lynx path.
> 
> Hope this helps :)
> -Jason
> 
> Daren Cotter wrote:
> > Thanks for the info Chris, it works!
> > 
> > How do I pass arguments to the script? I'm
> assuming
> > it'd just be:
> > 
> > test.php arg1 arg2
> > 
> > The stuff I've read says $argc should be the count
> of
> > the # of arguments, and $argv should be an array
> > holding them...but when I do a simple:
> > print "# of Arguments: $argc\n";
> > It prints nothing, not even 0
> > 
> > 
> > --- Chris Hewitt <[EMAIL PROTECTED]>
> wrote:
> > 
> >>>
> >>>On Wed, 25 Sep 2002, Daren Cotter wrote:
> >>>
> >>>
> >>>>My problem, is that I absolutely NEED to run a
> PHP
> >>>>script using crontab. The script needs to send
> >>>>numerous queries to a database every hour. Is
> >>>
> >>there
> >>
> >>>>any way I can accomplish this, directly or
> >>>
> >>indirectly?
> >>
> >>Are you sure its not already there? Commonly in
> >>/usr/bin. Try a "which 
> >>php" and see if it finds anything?
> >>
> >>HTH
> >>Chris
> >>
> > 
> > 
> > 
> > __________________________________________________
> > Do you Yahoo!?
> > New DSL Internet Access from SBC & Yahoo!
> > http://sbc.yahoo.com
> 
> 
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