Hi Kevin,
I find it a bit awkward to mix variables and arrays in a pseudo array. But I guess you have reasons... Anyhow, maybe this is what you want: $variable1="one"; $variable2="two"; $variable3 = array(); $variable3[0]="three"; $variable4 = array(); $variable4[0]="four"; $j=1; while($j<5){ if (is_array(${"variable".$j})) { print(${"variable".$j}[0] . "<br />"); } else { print(${"variable".$j} . "<br />"); }; $j++; } Timo Am Freitag den, 6. September 2002, um 20:37, schrieb Kevin Heflin: > Hoping someone can help me with this. Below I have an example > of what I'm trying to accomplish. > Bottom line.. I need to print out $variable3[0] and $variable4[0] > and my problem is that I'm trying to generate the variable > name. I can get this to work with $variable1 and $variable2 > which are not arrays, however that doesn't help me much. > > Any suggestions would be appreciated. > > Kevin > > > > <? > $variable1="one"; > $variable2="two"; > $variable3[0]="three"; > $variable4[0]="four"; > > $j=1; > while($j<5){ > print("${variable.$j} <BR>"); > $j++; > } > > > $j=1; > while($j<5){ > $k="\$variable".$j."[0]"; > print("$k <BR>"); > print("${variable.$k} <BR>"); > $j++; > } > ?> > > > -- PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php