Hallo, I don't know if it helps you, but normally you have to quote the variable in the SQL-Statement like: SELECT * FROM sessions WHERE sessionID = '$sessionID' Otherwise I always get an SQL-Error
Jean-Marc Godart wrote: > Hello everyone, > > I am a new PHP user, from Belgium. I am trying to manage a MySQL database with PHP, >and I kindly request your help to solve a little (probably very stupid) problem I >have been dealing with for a while already ... > > I have a MySQL database (called "sessions") with a auto-increment INT field called >"sessionID". I try to check if there is already a record in this database with a >given sessionID, which is called $sessionID in PHP. I use this query, which must be >wrong (but I cannot find out why !!!) : > > SELECT * FROM sessions WHERE sessionID = $sessionID > > Even though there is already a record with the right sessionID, my program does not >find it (I always get 0 when using mysql_num_rows() after the query). Though, if I >replace "$sessionID" by, for example 4, then that works and it says there is already >a record with that ID. > > I guess the problem comes from comparing two different kinds of variables, but I >can't fix it ... Could anyone please help ? By advance, thank you !!! > > Best regards from Belgium, > > > Jean-marc > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
