On Thursday 25 July 2002 00:34, Matthew Bielecki wrote: > I have a couple of scripts that fail with the error of: > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result > resource in... > > I'm new to both SQL and PHP and I'm wondering if I have some setting > turned off or what. > > Here's the piece of code that is failing (the second line fails): > > $result = mysql_db_query($dbname, "SELECT * FROM tablename ORDER BY id"); > $row = mysql_fetch_array($result);
It's a very good idea to add some error checking code it'll save you a lot of grief. See examples in manual for details. -- Jason Wong -> Gremlins Associates -> www.gremlins.com.hk Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * /* "Nine years of ballet, asshole." -- Shelly Long, to the bad guy after making a jump over a gorge that he couldn't quite, in "Outrageous Fortune" */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
