>The script was working great before PHP 4.2.x and not after that. So, I >looked through the code and came upon this variable, "$$var". I have no >idea what the purpose of the double "$" is for a variable. Anyone know?
> $var = "v".$counter."_high_indiv"; > $val3 = $$var; Read the manual about "variable variables" basically, they are creating a variable name like 'v1_high_indiv' (in $var) and then when they say $$var they really mean $v1_high_indiv It's probably not the source of your problem. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
