I still cant get it right,
in query.php i have this piece of code;
echo "<form action='test2.php' action='post'>
<select name='language'>
<option value='0'selected='yes'>one</option>
<option value='1'>two</option>
</select>
<input type=text name=query>
<input type=submit name=submit>
</form>";
and in test2.php i have this;
if ($_POST['language'] = 1)
{$lang = "EngP=1";}
else {$lang = "EngP=0";}
echo $lang ;
But it always echoes EngP=1 no matter what I choose, what is wrong here??
"Erik Price" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>
> On Wednesday, June 26, 2002, at 02:51 PM, Haddad Said wrote:
>
> > Hi, i am having a problem passing variables from a drop down menu in a
> > form;
> >
> > <from action=test.php action=post>
> > <select name=example>
> > <option selected> one</option>
> > <option> two</option>
> > </form>
>
> You should do it like this (be sure to properly quote your attributes,
> and use the 'value' attribute of the 'option' tag):
>
> print "<form action='test.php' method='post'>
> <select name='example'>
> <option selected='yes' value='1'>One</option>
> <option value='2'>Two</option>
> </select>
> </form>\n";
>
> In the "test.php" page, the selected value will be found in the
> $_POST['example'] variable.
>
>
> Erik
>
>
>
>
>
> ----
>
> Erik Price
> Web Developer Temp
> Media Lab, H.H. Brown
> [EMAIL PROTECTED]
>
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