Here is the function:
function print_new_story(){
$query = "SELECT * FROM news ORDER BY id DESC LIMIT 1";
$result = mysql_query($query);
$num_results = mysql_num_rows($result);
for ($i=0; $i < $num_results; $i++)
{
$row = mysql_fetch_array($result);
echo '<h2><a href="#">: ';
echo $row['title'];
if(!$row['date'] == 0){
echo ' - ';
echo date("d-M-y", $row['date']);
}
echo ' :</a></h2><br>';
include $row['int_location'];
}
}
and here is the error message:
Parse error: parse error in \\johnh\c\co2 busters\includes\functions.php on
line 81
----- Original Message -----
From: "Nick Wilson" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, May 29, 2002 11:08 PM
Subject: Re: [PHP] Parse Error(newbie)
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
>
> * and then [EMAIL PROTECTED] declared....
> > I get a parse error on this line
> >
> > $query = "SELECT * FROM news ORDER BY id DESC LIMIT 1";
> >
> > I believe that it is an error in the SQL statement
>
> Nothing wrong with that. Let's have the whole error msg and the code
> surrouding the line it says it's on please.... It might well not be on
> that line at all.
> - --
> Nick Wilson // www.tioka.com
>
>
>
> -----BEGIN PGP SIGNATURE-----
> Version: GnuPG v1.0.6 (GNU/Linux)
>
> iD8DBQE89NLaHpvrrTa6L5oRAiZ0AJ9fXPhupt203ghx8nNnDkgrtkgpsgCfQRFO
> tpYkUeHN5k9+EZxGuZbP34k=
> =QCuq
> -----END PGP SIGNATURE-----
>
> --
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