Or why not just use include_once() or require_once() ??
That's their purpose.

---
Scott Hurring
Systems Programmer
EAC Corporation
[EMAIL PROTECTED]
Voice: 201-462-2149
Fax: 201-288-1515

> -----Original Message-----
> From: Paul Roberts [mailto:[EMAIL PROTECTED]]
> Subject: Re: [PHP] Variable won't work in function, even when I global
> it?
> 
> try
> 
> eval("?>$footertext");
> 
> also take the code out of the function and try it, you may 
> need to global some more variables.
> 
> Paul Roberts
> [EMAIL PROTECTED]

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