$db = ("localhost","databasename","databasepassword");
mysql_select_db("your name?",$db);
$result = mysql_query("select column1, column2 from domain", $db);
while ($myrow=mysql_fetch_array($result))
echo $myrow["column1"]." - ".$myrow["column2"]."<br>";
--
Best regards,
George Nicolae
IT Manager
___________________
PaginiWeb.com - Professional Web Design
www.PaginiWeb.com
"Rodrigo" <[EMAIL PROTECTED]> wrote in message
000401c1f2cf$28b83f00$d86bbbac@rodirgo">news:000401c1f2cf$28b83f00$d86bbbac@rodirgo...
> Hi guys, what I need is how to make the link between the php and the
> Database.
>
> Is this the code for it? ro something like that? Help me guys...
>
> If you could tell me what each command line do I'd appreciate it, cause
> I got almost all from a friend, but is incomplete.
>
> The code follows this message.
>
>
> $db = ("localhost","databasename","databasepassword");
> mysql_select_db("your name?",$db);
> $result = mysql_query("select column1, column2 from domain", $db);
> echo "column 1 - column 2";
>
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
