Thank you Jason and Kevin for your time and help.
Does this look like what I should have?
if(isset($update))
for ($i=0; $i<count($id); $i++)
{
if ($id[$i] == $row[id])
{
$query = "UPDATE {$config["prefix"]}_shop SET price = $price[$i]
where uid = {$session["uid"]} AND id = $id[$i]";
$ret = mysql_query($query) or die(mysql_error());
}
else
{
echo "<TD width=30%><font size=2><CENTER><input=\"hidden\"
name=\"id[$i]\" value=\"$id\"><input type=\"text\" value=\"\"
name=\"price[$i]\" size='8' MAXLENGTH='8'><BR></a></CENTER></font></TD>";
Jennifer
"Kevin Stone" <[EMAIL PROTECTED]> wrote in message
004301c1e633$e1e20090$6601a8c0@kevin">news:004301c1e633$e1e20090$6601a8c0@kevin...
> -------------
> I picked up your question soon after you submited it then my internet went
> down so I wasn't able to send it. Looks like it's been answered by
someone
> else since then but here you go anyway. I didn't want to feel as though
I'd
> wasted my time. :D
> -kevin
> -------------
>
> Looks like you want to extract the values from the $price array in the
same
> order as you extracted the associated rows from the database. At first
> glance I can say you aren't passing enough information to be able to
> determine an order for updating. You'll need to send the product ids along
> with the prices and then create a counter to loop through the ids array
and
> test each case.
>
> I would sugget you build an $id[] list the same way as the $price[] list
but
> generate them as hidden fields. Then within the if(isset($update))
> statement loop through all $id values for each itteration of the while
> loop...
>
> for ($i=0; $i<count($id); $i++)
> {
> if ($id[$i] == $row[id])
> {
> // we know that there are the same number of ids as there are
prices
> so we can use $i for the $price index as well.
> $query = "UPDATE $table SET price = $price[$i] WHERE id =
$id[$i]";
> // do update..
> }
> }
>
> -Kevin
>
> ----- Original Message -----
> From: "Jennifer Downey" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Wednesday, April 17, 2002 10:11 AM
> Subject: [PHP] Re: Using one submit button
>
>
> > I have no takers on this one?
> >
> > Just to let you know I have been working on this to here is some new
code.
> > What I need this to do is update the price in the db table.
> > if I have on item it is fine. If I have two items it won't update the
> first
> > items price but will the second. if I try to enter a price in the first
> > items textbox it doesn't update and then deletes the second item's
price.
> >
> > If I have 15 items and using one submit button how do I get this to
> update
> > all items that are listed?
> >
> > $query = "SELECT uid, id, name, image, type, quantity, price FROM
> > {$config["prefix"]}_shop WHERE uid = {$session["uid"]}";
> > $ret = mysql_query($query);
> > while($row = mysql_fetch_array($ret))
> > {
> > $uid = $row['uid'];
> > $id = $row['id'];
> > $name = $row['name'];
> > $image = $row['image'];
> > $iquantity = $row['quantity'];
> > $itype = $row['type'];
> > $iprice = $row['price'];
> >
> > if($update)
> > {
> > $eprice = '$price[]';
> > $query = "UPDATE {$config["prefix"]}_shop SET price = '$eprice'
> > where uid = {$session["uid"]} AND id = '$id'";
> > $ret = mysql_query($query) or die(mysql_error());
> > }
> > else
> > {
> >
> > echo "<TABLE BORDER='0' WIDTH='95%' CELLPADDING='0'
> > CELLSPACING='0'><TR>";
> > echo "<TD width=20%><img src='$image'></TD>";
> > echo "<TD width=30%><font size=2>$name</font></TD>";
> > echo "<TD width=20%><font
> > size=2><CENTER>$iquantity</CENTER></font></TD>";
> > echo "<TD width=30%><font size=2><CENTER><a
> > href='$PHP_SELF?id=$id&remove=yes'>X</a></CENTER></font></TD>";
> > echo "<TD width=30%><font size=2><CENTER><input
type=\"text\"
> > value=\"\" name=\"price[]\" size='8'
> > MAXLENGTH='8'><BR></a></CENTER></font></TD>";
> > echo "</TD></TR></TABLE>";
> > echo "<input=\"hidden\" name=\"remove\" value=\"yes\">";
> > }
> > }
> > echo "<CENTER><INPUT TYPE=\"submit\" NAME=\"update\" VALUE=\"Updat
> > Prices\">";
> > echo "</form>";
> > "Jennifer Downey" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > Hi all,
> > >
> > > I thought I was going to give php a break today but I can't it's too
> > > adicting.
> > >
> > > I am having a little problem with a submit button in which it is
suppose
> > to
> > > update records from a form.
> > >
> > > Here is the code
> > >
> >
>
> --------------------------------------------------------------------------
> > --
> > > ----
> > >
> > >
> > > echo "<BR><BR><a href=\"locker.php\">My Locker</a> | <a
> > > href=\"myshop.php\">My Shop</a> | <a href=\"items.php\">My
> > > Items</a><BR><BR>";
> > > echo "<TABLE BORDER='0' WIDTH='95%' CELLPADDING='0'
> > CELLSPACING='0'><TR><TD
> > > width=20%><B><font size=2>Image</font></B></TD><TD width=30%><B><font
> > > size=2>Name</font></B></TD><TD width=20%><B><font
> > > size=2><CENTER>Quantity</CENTER></font></B></TD><TD width=30%><B><font
> > > size=2><CENTER>Remove Item</CENTER></font></B></TD><TD
> width=30%><B><font
> > > size=2><CENTER>Price</CENTER></font></B></TD></TR></table>";
> > > echo "<FORM action='$PHP_SELF' METHOD='post'>";
> > >
> > > $query = "SELECT uid, id, name, image, type, quantity FROM
> > > {$config["prefix"]}_shop WHERE uid = {$session["uid"]}";
> > > $ret = mysql_query($query);
> > > while($row = mysql_fetch_array($ret))
> > > {
> > > $uid = $row['uid'];
> > > $id = $row['id'];
> > > $name = $row['name'];
> > > $image = $row['image'];
> > > $iquantity = $row['quantity'];
> > > $itype = $row['type'];
> > >
> > >
> > > echo "<TABLE BORDER='0' WIDTH='95%' CELLPADDING='0'
> > > CELLSPACING='0'><TR>";
> > > echo "<TD width=20%><img src='$image'></TD>";
> > > echo "<TD width=30%><font size=2>$name</font></TD>";
> > > echo "<TD width=20%><font
> > > size=2><CENTER>$iquantity</CENTER></font></TD>";
> > > echo "<TD width=30%><font size=2><CENTER><a
> > > href='$PHP_SELF?id=$id&remove=yes'>X</a></CENTER></font></TD>";
> > > echo "<TD width=30%><font size=2><CENTER><input
> type=\"text\"
> > > value=\"\" name=\"price\" size='6'
> > > MAXLENGTH='8'><BR></a></CENTER></font></TD>";
> > > echo "</TD></TR></TABLE>";
> > >
> > > echo "<input=\"hidden\" name=\"remove\" value=\"yes\">";
> > > }
> > > echo "<CENTER><INPUT TYPE=\"submit\" NAME=\"update\" VALUE=\"Updat
> > > Prices\">";
> > > echo "</form>";
> > > if($update)
> > > {
> > > $query = "UPDATE {$config["prefix"]}_shop SET price =
'$price'
> > > where uid = {$session["uid"]}";
> > > $ret = mysql_query($query);
> > > }
> > >
> > >
> > >
> >
>
> --------------------------------------------------------------------------
> > --
> > > ----
> > >
> > >
> > >
> > > What I need this to do is update the price in the db table.
> > > if I have on item it is fine. If I have two items it won't update the
> > first
> > > items price but will the second. if I try to enter a price in the
first
> > > items textbox it doesn't update and then deletes the second item's
> price.
> > >
> > > If I have 15 items and using one submit button how do I get this to
> update
> > > all items that are listed?
> > >
> > > TIA
> > > Jennifer
> > >
> > > --
> > > The sleeper has awaken
> > >
> > >
> > > ---
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> > >
> > >
> >
> >
> > ---
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> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>
>
>
---
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