Uh why do you think that? Try print chr("65"); works the same as as print chr(65);
Rick Emery wrote: > chr() expects you to pass it a numeric value. You are passing it a string. > For instance, > if $text= "-", then you are trying to do: chr("45"), which is not the > same as chr(45). > Hence, ereg_replace() fails and simply returns the original string, $text. > > -----Original Message----- > From: Ando [mailto:[EMAIL PROTECTED]] > Sent: Thursday, March 28, 2002 7:08 AM > To: [EMAIL PROTECTED] > Subject: Re: [PHP] ereg_replace or chr bug? > > Not sure what you mean here > $text= ereg_replace('&#([0-9]+);' , chr('\1') , $text); > > should replace for example "A" with chr('65') (\1 means everything in > brackets in regular expression), which is 'A' . > > Rick Emery wrote: > > > From the manual for chr() > > > > Returns a one-character string containing the character specified by > ascii. > > > > It replaces one (1) character, not a string > > > > > -----Original Message----- > > From: Ando [mailto:[EMAIL PROTECTED]] > > Sent: Thursday, March 28, 2002 6:59 AM > > To: [EMAIL PROTECTED] > > Subject: [PHP] ereg_replace or chr bug? > > > > Ok, what i wanna do is replace the codes in html with ascii equivalents: > > > > $text= ereg_replace('&#([0-9]+);' , chr('\1') , $text); > > But somehow it doesnt work, i have no idea why. > > > > When i use > > $text= ereg_replace('&#([0-9]+);' , '\1' , $text); > > it replaces everything correctly > > > > But > > $text= ereg_replace('&#([0-9]+);' , chr('\1') , $text); > > just replaces everything with an empty string > > > > using php 3.0.12 > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php