Uh why do you think that?
Try
    print chr("65");
works the same as as
    print chr(65);

Rick Emery wrote:

> chr() expects you to pass it a numeric value.  You are passing it a string.
> For instance,
> if $text= "&#45", then you are trying to do:  chr("45"), which is not the
> same as chr(45).
> Hence, ereg_replace() fails and simply returns the original string, $text.
>
> -----Original Message-----
> From: Ando [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, March 28, 2002 7:08 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] ereg_replace or chr bug?
>
> Not sure what you mean here
> $text= ereg_replace('&#([0-9]+);' , chr('\1') , $text);
>
> should replace for example "A" with chr('65') (\1 means everything in
> brackets in regular expression), which is 'A'   .
>
> Rick Emery wrote:
>
> > From the manual for chr()
> >
> > Returns a one-character string containing the character specified by
> ascii.
> >
> > It replaces one (1) character, not a string
>
> >
> > -----Original Message-----
> > From: Ando [mailto:[EMAIL PROTECTED]]
> > Sent: Thursday, March 28, 2002 6:59 AM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP] ereg_replace or chr bug?
> >
> > Ok, what i wanna do is replace the codes in html with ascii equivalents:
> >
> > $text= ereg_replace('&#([0-9]+);' , chr('\1') , $text);
> > But somehow it doesnt work, i have no idea why.
> >
> > When i use
> > $text= ereg_replace('&#([0-9]+);' , '\1' , $text);
> > it replaces everything correctly
> >
> > But
> > $text= ereg_replace('&#([0-9]+);' , chr('\1') , $text);
> > just replaces everything with an empty string
> >
> > using php 3.0.12
> >
> > --
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>
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