Yeah, that's what I looked at before posting - but there's a catch: 
"Returns the user ID of the **current script**, or *FALSE* on error". :-(

Bogdan

Martin Towell wrote:

> try: http://www.php.net/manual/en/function.getmyuid.php
>
> -----Original Message-----
> From: Bogdan Stancescu [mailto:[EMAIL PROTECTED] ]
> Sent: Wednesday, February 27, 2002 10:33 AM
> To: Stewart Gateley
> Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: Re: [PHP] is_uploaded_file() emulation?
>
>
> Thank you - but that wasn't the question - as you can see, I started the
> second paragraph with a reference to that function - my problem is what
> I compare the result to - i.e. how do I find out *my* UID, not the 
> file's.
>
> Mr. Kelly's solution should work, but it's rather absurd (from a PHP
> point of view) to have to create a file just to find out what my uid
> is... I'm sure there should be a more reasonable method - but I don't
> know it. Hoping somebody does... ;-)
>
> Thanks!
>
> Bogdan
>
> Stewart Gateley wrote:
>
> >$owner = fileowner ($file);
> >
> >returns a string containing the owner or false. see
> > http://www.php.net/manual/en/ref.filesystem.php
> >
> >-- Stewart
> >
> >--- Bogdan Stancescu <[EMAIL PROTECTED]> wrote:
> >
> >>Hello all!
> >>
> >>How do I find out if a file was actually uploaded /without/ using
> >>is_uploaded_file()?
> >>
> >>My first though is that I should use fileowner() on the file and see
> >>if
> >>it's the same as the user who runs PHP (Apache) - but how do I find
> >>that
> >>out? I don't want to use exec("id -u") either because the syntax may
> >>be
> >>different for distinct systems and I'd like to avoid system calls if
> >>possible.
> >>
> >>I'm open to any suggestions to solve the original problem - not
> >>necessarily using UID's.
> >>
> >>Thanks!
> >>
> >>Bogdan
> >>
> >>
> >>
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> >>
> >
> >
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