On Thu, 21 Feb 2002 12:10:53 +1100, Martin Towell wrote: >$z = (int)($x / $y); // should work > >or > >$z = $x / $y; >settype($z, "integer");
or $z = intval($x / $y); bvr. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
