Phil, Thanks for the suggestion. I tried it and it worked the first time, but as I changed to a second directory ./maps2/ it fell apart again.
Also, what I didn't state at the start, was that map1.jpg is actually a variable, $map. It's just that when I was pounding on it, I settled on using hard names instead of variables figuring that I was at least limiting the source for error. The problem is the same though, it seems to work then dies. Not my machine either, I ftp the file to olm and see the results on line. Thanks for your help. If you have any other suggestions, please let me know. Hugh ----- Original Message ----- From: "Philip Hallstrom" <[EMAIL PROTECTED]> To: "hugh danaher" <[EMAIL PROTECTED]> Sent: Friday, February 08, 2002 5:05 PM Subject: Re: die! die! directory! > what if you do this: > > print "<input type=image src=\"./maps/map1.jpg\" name=coordinate >"; > > ?? > > On Fri, 8 Feb 2002, hugh danaher wrote: > > > Help! > > > > I've been beating on a problem all day and think I've isolated the problem to the following line: > > > > print "<input type=image src=./maps/map1.jpg name=coordinate >"; > > > > If I call the statement as is, I get a little red x where my map should be. In earlier calls to the same directory, I can get a server error, misconfiguration... > > > > if I change the line to: > > > > print "<input type=image src=map1.jpg name=coordinate >"; > > > > I see the image. > > > > is there a way to declare the path before asking for the file, or a better way to state the file location. > > > > Any help will be greatly appreciated. > > > > Hugh > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
