RE: [PHP] Login Script

[Jerry Verhoef (UGBI)]

Line 10 is?

$sid (login($user, $pass)); <--- missing =

-----Original Message-----
From: Necro [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 21, 2001 1:40 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Login Script


Lo all,

I am trying to get the following script to work..

<?
if ($HTTP_POST_VARS["action"] == 1)
{
        checklogin($HTTP_POST_VARS["user_name"],
$HTTP_POST_VARS["password"]);
        exit;
}

function checklogin($user, $pass)
{
        $sid (login($user, $pass));

        if ($sid != -1)
        {
                header("Location: http://localhost/hq.php?sid=$sid";);
        }
        else
        {
                header("Location: http://localhost/error.php";);
        }
}

function login($user, $pass)
{
        $db = "zoner2";
        $SQL = "SELECT * FROM users WHERE user_name='".$user."' AND
password='".$pass."'";
        $connection = db_connect();

        $query = mysql_db_query($db, $SQL, $connection);

        if (mysql_num_rows($query) != 1)
        {
                return -1;
        }

        $row = mysql_fetch_array($query);

        $user_id = $row["user_id"];

        $sid = md5("blah blah".$user_id.$time());

        $remip = REMOTE_ADDR();

        $ttime = date("YmdHis");

        $SQL2 = " INSERT INTO details ";
                $SQL2 = $SQL2 . " (user_id, sid, ttime, remip) VALUES ";
                $SQL2 = $SQL2 . " ('$user_id','$sid','$ttime','$remip') ";
        #######
        $result2 = mysql_db_query($db,"$SQL2",$connection);
        if (!$result2) { echo("ERROR: " . mysql_error() . "\n$SQL\n");
mysql_close($cid); exit; }
        #######
        SetCookie("TheLoginCookie", "$user_id:$sid:$ip", time()+3600);

        return $sid;
}

?>

But every time I open the login page and try to login I get the following
error.

Fatal error: Call to undefined function: () in d:\htdocs\web\login1.inc on
line 10

Can anyone explain why this is??

Thankyou.

Andrew

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