Yep...

And i don´t get any wiser. I have tried all sorts of combinations. But i
can´t get the damn values printed.

This is how the print_r of $num_vals looks:

( [0] => Array ( [0] => 0 [COUNT(*)] => 0 )
[1] => Array ( [0] => 0 [COUNT(*)] => 0 )
[2] => Array ( [0] => 5 [COUNT(*)] => 5 )
[3] => Array ( [0] => 6 [COUNT(*)] => 6 )
[4] => Array ( [0] => 7 [COUNT(*)] => 7 )
[5] => Array ( [0] => 7 [COUNT(*)] => 7 )
[6] => Array ( [0] => 9 [COUNT(*)] => 9 )
[7] => Array ( [0] => 11 [COUNT(*)] => 11 )
[8] => Array ( [0] => 8 [COUNT(*)] => 8 )
[9] => Array ( [0] => 9 [COUNT(*)] => 9 ) )

Ideas?

Regards
Daniel

> -----Original Message-----
> From: Jack Dempsey [mailto:[EMAIL PROTECTED]]
> Sent: den 13 december 2001 16:30
> To: Daniel Alsén; PHP
> Subject: RE: [PHP] Can i do this?
>
>
> didn't check your code specifically, but you can definitely have arrays
> nested inside of arrays...to see how to print them out use something like
> print_r to look  at the structure...
>
> -----Original Message-----
> From: Daniel Alsén [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, December 13, 2001 10:12 AM
> To: PHP
> Subject: [PHP] Can i do this?
>
>
> Hi,
>
> can i do this?
>
> $num_vals = array ();
> for ($i=0; $i<10; $i++)
> {
>   $shot_count = "SELECT COUNT(*) FROM statistik WHERE
> shooter='$shooter_login' && shot_one = '$i' || shooter='$shooter_login' &&
> shot_two = '$i' || shooter='$shooter_login' && shot_three = '$i' ||
> shooter='$shooter_login' && shot_four = '$i' ||
> shooter='$shooter_login' &&
> shot_five = '$i'";
>   $result = mysql_query($shot_count);
>   $num_vals[$i] = mysql_fetch_array($result);
> }
>
> I guess it´s the last row that is troubling - getting an array into an
> array. If the code is good - how do i echo the results?
>
> # Daniel Alsén    | www.mindbash.com #
> # [EMAIL PROTECTED]  | +46 704 86 14 92 #
> # ICQ: 63006462   | +46 8 694 82 22  #
> # PGP: http://www.mindbash.com/pgp/  #
>
>
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