When you attempt to print or echo an array the result is simply "array". You have to iterate through the elements of the array to see what each element contains. Read the array chapter in the manual for more information.
Fred Jose <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > I try to give it a value with a var, but it doesn't work. > > The code is something like this. > > $y=str_pad($y,5,".txt"); \\ To give it a filename from a var that contains > only 1 number (with 1 digit) > If in this step I do a "echo $y, it shows the correct string. Suposing it is > 2, it shows 2.txt > > $temp[]=file($y); \\ To load the file into the array. > > But after the file nothing happens, the array only contains "Array". > > Sorry for my bad english. > Jose. > > Olinet S.L. > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
