Or..

$required = array($name,$addr,$phone);

foreach($required as $x) {
    if(!$x) {
  print "error";
 }
}

~Ryan

----- Original Message -----
From: "Philip Hallstrom" <[EMAIL PROTECTED]>
To: "Brandon Lamb" <[EMAIL PROTECTED]>
Cc: "PHP List" <[EMAIL PROTECTED]>
Sent: Tuesday, November 20, 2001 2:37 PM
Subject: [PHP] Re: Re: Re: How do I convert from perl to php?


> No, but this:
>
> $required = array('name','address','phone');
> foreach( $required as $key )  {
> if( empty($HTTP_POST_VARS[$key]) )  {
> print("Sorry, you left key empty.");
> }
> }
>
> should work.
>
>
> On Tue, 20 Nov 2001, Brandon Lamb wrote:
>
> > What about this?
> >
> >   $required = array('name','address','phone');
> >   while ( list($key, $value) = each ($required) )  {
> >     if ( empty($value) ) {
> >       print("Sorry, you left $key empty.");
> >     }
> >   }
> >
> > ----- Original Message -----
> > From: "Philip Hallstrom" <[EMAIL PROTECTED]>
> > Cc: <[EMAIL PROTECTED]>
> > Sent: Tuesday, November 20, 2001 2:22 PM
> > Subject:  Re: Re: How do I convert from perl to php?
> >
> >
> > You could do something like this... there are lots of ways to validate
> > your data...
> >
> > while( list($key, $value) = each($HTTP_POST_VARS) )  {
> > if( empty($value) )  {
> > print("Sorry, you left $key empty.");
> > }
> > }
> >
> >
> >
> >
> > --
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> >
>
>
>
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