oh duh, why is it always the simplest reason. :)
fixed it and it runs good now.
thank you sir!
Jim Lucas wrote:
> sorry didn't notice the & in the args
> you'll want this instead.
>
> > function scan_string(&$str) {
> > $forbid = array ("coke", "tylenol", "ford");
> > $swap = array ("pepsi", "advil", "chevrolet");
> > for ($i = 0; $i < count ($forbid); $i++) {
> > $str = eregi_replace($forbid[$i],$swap[$i],$str);
> > }
> > }
>
> Jim
> ----- Original Message -----
> From: "phantom" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Friday, November 16, 2001 2:16 PM
> Subject: [PHP] eregi_replace probs
>
> > function scan_string(&$str) {
> > $forbid = array ("coke", "tylenol", "ford");
> > $swap = array ("pepsi", "advil", "chevrolet");
> > for ($i = 0; $i < count ($forbid); $i++) {
> > eregi_replace($forbid[$i],$swap[$i],$str);
> > }
> > }
> >
> > I run this script, and I know the array's load up and the for...do loop
> > runs ok. As does the passing variable ($str).
> >
> > I enter a test script such as "I like coke." and my returned value
> > remains "I like coke."
> >
> > It appears the eregi_replace is the problem.
> >
> > Any idea why?
> >
> >
> > --
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> >
> >
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