select table1.* from table1
LEFT JOIN table2 ON table1.id=table2.id
where table2.id is NULL;
http://www.mysql.com/doc/J/O/JOIN.html
-----Original Message-----
From: Srinivasan Ramakrishnan [mailto:[EMAIL PROTECTED]]
Sent: 18 October 2001 17:06
To: [EMAIL PROTECTED]
Subject: [PHP] MySQL query
Hi all,
I'm looking at the following scenario: I have MySQL two tables with
usernames in both of them, I need to get usernames(A) - usernames(B)
In Oracle I would use:
SELECT username FROM user
MINUS
SELECT username FROM task_assignment
Since MySQL does not support MINUS, I tried using the following
SELECT DISTINCT A.username FROM user A
WHERE A.username
NOT IN(SELECT B.username FROM task_assignment B);
Here's what I get from MySQL:
mysql> SELECT DISTINCT A.username FROM user A WHERE
A.username NOT IN(SELECT B.username FROM task_assignment B);
ERROR 1064: You have an error in your SQL syntax near 'SELECT B.username
FROM ta
sk_assignment B)' at line 1
It appears to me that MySQL's NOT IN cannot handle recordsets, so as a
fix
I'm currently doing like so, which works, but I'd really like to get it
as a
single MySQL statement.
$query = "SELECT DISTINCT username FROM task_assignment";
$db_result = mysql_query($query);
$data = mysql_fetch_array($db_result);
$not_in = $data[0];
while($data = mysql_fetch_array($db_result)){
$not_in .= ', ' . $data[0];
}
$query = "SELECT DISTINCT username FROM user";
$query .= "WHERE username NOT IN($not_in)";
Any help will be appreciated.
Cheers,
-Srini
--
http://www.symonds.net/~sriniram
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