It is the same thing.
trim() is enough to make it work.


Maxim Maletsky
www.PHPBeginner.com



-----Original Message-----
From: Mauricio T?llez Jim?nez [mailto:[EMAIL PROTECTED]] On
Behalf Of EDUMEXICO
Sent: mercoledì 3 ottobre 2001 19.53
To: Dominik
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Problem when displaying the $ character


Hi, try this:

<?

echo "
<select name=\"menu\">
<option value=\"$item1\">Item 1</option>
<option value=\"$item2\">Item 2</option>
</select>";

?>

I hope this can help you. Cheers

On Wed, Oct 03, 2001 at 11:08:27AM -0700, Dominik wrote:
> Through php, I run a function that creates a list of items in a select

> menu as follows:
> 
> <select name="menu">
> <option value="<? echo "$item1"; ?>">Item 1</option>
> <option value="<? echo "$item2"; ?>">Item 2</option> </select>
> 
> but here is how the source code looks:
> 
> <select name="menu">
> <option value="
> item1">Item 1</option>
> <option value="
> item2">Item 2</option>
> </select>
> 
> It looks like php takes the $ character and inserts a return for it.  
> This though disrupts the value of the form element.  Is there anyway 
> to make this code appear like it should (with the option tag all on 
> one line instead of 2)?
> 
> Thanks!
> Dominik
> 
> 
> 
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-- 
Mauricio Téllez Jiménez
Seguimiento Técnico EDUMEXICO
[EMAIL PROTECTED]
[EMAIL PROTECTED]
[EMAIL PROTECTED]
Zamora No. 25, Col. Centro
C.P. 91000, Xalapa, Ver.
Tel. 52(28)17-86-87, 17-73-80
Fax. 52(28)18-64-13


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