You can allso do like this:
$i = 1;
${"test". $i} = "123";
echo $test1;
___________________________________________
Marcus Rasmussen
[EMAIL PROTECTED]
On 21-09-01 at 11:21 _lallous wrote:
>you can always use eval to create a variable too!
>
><?
>$i = 1;
>eval("\$test$i=123;");
>echo $test1;
>?>
>
>"Neil Freeman" <[EMAIL PROTECTED]> wrote in message
>[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>> Hi there,
>>
>> How do I generate variable names 'on the fly'? I wish to have variable
>> names along the lines of $genre_category_1, $genre_category_2,
>> $genre_category_3 etc.
>>
>> Ideally it would be along the lines of this...
>>
>> #######################
>> $current_field_number = 1;
>> $genre_number_fields = 7;
>>
>> while ($current_field_number < $genre_number_fields)
>> {
>> //this var will change on every loop
>> $genre_desc = $db_movies_genres->Record[$current_field_number];
>>
>> //something along the lines of...(you get the idea)
>> $str_category = "genre_category_" . $current_field_number;
>> $$str_category = $genre_desc;
>>
>> $current_field_number++;
>> }
>> #######################
>>
>> Any help would be greatly appreciated.
>>
>> Neil
>> --------------------------------
>> Email: [EMAIL PROTECTED]
>> [EMAIL PROTECTED]
>> --------------------------------
>>
>>
>
>
>
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